[Termtools] Conflict in ITS
Akihisa Yamada
akihisayamada at nii.ac.jp
Thu Mar 28 18:02:19 CET 2019
Dear Albert,
are you going to fix this? Probably you only need to add a
configuration. If it's done, please let me know.
Best,
Akihisa
On 2019/03/25 17:54, Albert Rubio wrote:
> Samir is right. There is a subtle bug in VeryMax due to the use of the
> graph resulting form the conditional termination proof to then prove
> non-termination. This problem appears rarely and it disappears when the
> use of this graph is disabled adding the flag "-nt-graph original" to
> the call.
>
> Best,
>
> Albert
>
>
> On 23/3/19 15:48, Akihisa Yamada wrote:
>> Thanks a lot Genaim! Any comment, Albert?
>>
>> Best,
>> Akihisa
>>
>> On Mar 23, 2019, at 21:46, Samir Genaim <genaim at gmail.com
>> <mailto:genaim at gmail.com>> wrote:
>>
>>>
>>> As far I can see this ITS is terminating. It is easier to explain
>>> using the following equivalent program. The symbol * means
>>> non-deterministic integer choice, and the variables are: walker_0 is
>>> w, seq_0 is s, i_0 is i, choice_0 is c and z_0 is z (N_0 was removed
>>> since it is the constant 2, and pos_0 was removed since it is not used)
>>>
>>>
>>> w=1; s=1; i=1; z=*; assert(z >= 0); // edge 14->13
>>> while ( 1 =< w && w =< 2 ) { // nodes 13, 17, 18
>>> c = *; assert(0 <= c && c <= 1) // edge 17->16
>>> if ( z >= 1 ) {
>>> z--; // edge 16->12
>>> } else { // z <= 0, edge 16->15
>>> if ( i <= 0 ) {
>>> s++; i=s; z=*; assert(z >= 0); // one of edges 15->12
>>> } else if ( i >= 1 and c <= 0 ) {
>>> i--; // one of edges 15->12
>>> } else {
>>> break; // implicit exit at node 15 (blocking behaviour)
>>> }
>>> }
>>> if ( c <= 0 ) {
>>> w--; // one of edges 12->13
>>> } else {
>>> w++; // one of edges 12->13
>>> }
>>> }
>>>
>>>
>>> First, instructions w-- and w++ must alternate in consecutive
>>> iterations, otherwise, the loop terminates since w will become either
>>> 0 or 3.
>>>
>>> If the loop does not terminate, eventually we reach a state in which
>>> i=2 and z=0, which means that the following instruction has to
>>> execute in two consecutive iterations
>>> else if ( i >= 1 and c <= 0 ) {
>>> i--;
>>> } else {
>>> break;
>>> }
>>>
>>> if it does not 'break' out of the loop, then c=0 in these two
>>> iterations and thus w-- is executed twice in a row and the program
>>> terminates with w=0.
>>>
>>>
>>
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